Friday, January 8, 2010

Number 40 on the AP from Friday

40. So we set up the equation in class as
45=50e^(9k)
45/50=e^(9k)
.9=e^(9k)
ln.9 = ln (e^9k)
ln.9 = 9k
k=ln.9/9

Then you set up the second equation as
20 = 50e^(ln.9/9)t
20/50 = e^(ln.9/9)t
.4 = e^(ln.9/9)t
ln.4 = ln e^(ln.9/9)t
ln.4 = (ln.9/9)t
t = 78

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