1.Identify the equation
2. Use the formula f(x)+f ' (x)dx
3. Determine your dx in the problem
4. Then determine your x in the problem
5. Plug in everything you get
6. Solve the equation
Related Rates:
1. Identify all of the variables and equations
2. Identify the things that you are looking for
3. Sketch a graph and then label that graph
4. Create and write an equation using all of the variables
5. Take the derivative of this equation with respect to time
6. Substitute everything back in
7. Solve the equation
Tangent line Example:
Find the line tangent to the graph y=2x2+4x+6 at x=1.
1. Identify the equation and point of tangency. If not given a y value, plug the x value into the original equation.
y=2x2+4x+6 y=2(1)2
2. Differentiate you equation.
dy/dx=4x+4
3. Plug in x value then solve for dy/dx.
dy/dx=4(1)+4=8
Find the line tangent to the graph y=2x2+4x+6 at x=1.
1. Identify the equation and point of tangency. If not given a y value, plug the x value into the original equation.
y=2x2+4x+6 y=2(1)2
2. Differentiate you equation.
dy/dx=4x+4
3. Plug in x value then solve for dy/dx.
dy/dx=4(1)+4=8
i need help with alot but lets start with intergration
Integration is very easy once you get the hang of it... so lets say you have the function x^2+3x+5.. you add 3 to the exponent 2, and put the reciprocal in front.. you ad the exponent 2 to the 3x and multiply the 3 times 1/2. You would then add a x to the 5. The final answer would look like 1/3x^3+3/2x^2+5x. Hope this helps!
ReplyDeletewell the best way to get good at integration is to practice with them if you come see me at school i can give you some problems and help you work them
ReplyDeletethis concept takes a little while to get use to. It just takes practice. I dont fully understand it myself. The one thing that helps me grasp this concept is just always remember that an intergral is oposite of a derivative. So somebody derived a function to get to that intergral and then just thing of the main function. Think of what functions derivative looks like this intergral.
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