Sunday, February 7, 2010

Post Number Twenty Five

So i'm watching the superbowl and people oh so conveniently reminded me about the blog. So here it goes:

Max and mins are on every test:

First, find critical values by using the first derivative test: take the derivative set equal to zero and solve for the variable.Second, plug both intervals as well as the critical values into your original equation. Next, be sure to keep the value after substitution with each appropriate number. To determine which constitute a max and which constitute a min, you must look and point out those of which have the lowest values-min- and those of the highest value-max.

I can tell you how to do tangent lines but for some reason I never know how to do it on the tests:

Take the derivative of the equation like normal.
Plug in the x value which gives you your slope.
Use the slope you get and the point given and plug into slope intercept form (y-y1)=slope(x-x1).
If a point is not given and only an x value is given plug the x value into the original which will give you a y value creating a point.

Related Rates:

1. Identify all variables and equations.
2. Identify what you are looking for.
3. Make a sketch and label.
4. Write an equations involving your variables.
*You can only have one unknown so a secondary equation may be given
5. Take the derivative with respect to time.
6. Substitute in derivative and solve.

I still need help with ln and e integration and differentiation. Any volunteers?

Oh and WHO DAT (:

2 comments:

  1. For ln integration you check to make sure the top is the derivative of the bottom and if it is put it in this format ln|insert equation/terms here|
    Oh, and you can basically bend the problem to fit it..you can almost randomly add a term here and there
    ^^
    I'm a little confused with the other 2 topics myself, otherwise I'd help with those too =/

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  2. one thing you have to do is make sure the top is the der of thee bottom. then use ln and put your equation in absolute value thinggs.

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