so, saints just won the superbowl :) woooooh!
this week we did the same thing, worked on ap tests, and went over them
here's some stuff:
whatever e is raised to is your u. du is derivative of u
absolute maxs and mins:
1. Find critical values by using the first derivative test: take the derivative set equal to zero and solve for the variable.
2. Plug both intervals as well as the critical values into your original equation
3. Be sure to keep the value after substitution with each appropriate number.
4. To determine which constitute a max and which constitute a min, you must look and point out those of which have the lowest values-min- and those of the highest value-max.
1. Find critical values by using the first derivative test: take the derivative set equal to zero and solve for the variable.
2. Plug both intervals as well as the critical values into your original equation
3. Be sure to keep the value after substitution with each appropriate number.
4. To determine which constitute a max and which constitute a min, you must look and point out those of which have the lowest values-min- and those of the highest value-max.
linearization:
1. Pick out the equation
2. f(x)+f`(x)dx
3. Figure out your dx
4. Figure out your x
5. Plug in everything you get
1. Pick out the equation
2. f(x)+f`(x)dx
3. Figure out your dx
4. Figure out your x
5. Plug in everything you get
i don't understand tram and mram.
MRAM mainly just take the interval and break it up into the amount of subintervals then find the middle of the subintervals and plug into the formula
ReplyDeleteTo find the midpoints, add the two numbers and divid by two. THe way you break them up is to keep adding delta x from a to b.
ReplyDeleteTRam doesn't exist...assuming you are talking about trapezoidal...it's just a formula like the other ones.
ReplyDeletedeltaX/2 [f(a) + 2f(a+dX) + 2f(a+2dX) + ... + f(b))