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Some keywords I never understood:
Local minimum- first derivative, set equal to zero, solve, set up intervals and check
Maximum speed- absolute value of velocity
Linearization- find the equation of the tangent line
How Many? – integrate
Lim h> 0 + h – definition of derivative- take derivative of what is behind the parenthesis
Maximum value – find the y- value at the max; take derivative, set equal to 0, solve for x, plug in to find y.
Maximum acceleration- where is maximum slope
Starting point-position- related to original function; zeros of velocity will give you max and mins of position
Vertical tangents- take implicit derivative
Rate- take derivative

Somethings I know how to do:
Lim
x>infintity (20x^2 – 13x + 5)/(5 – 4x^3)

The limit is 0 because of the limit rule when the top degree is smaller than the bottom degree the limit is 0. 2<3

Limh>0 (ln(2+h) – ln2)/h is 1/2 .

You take the derivative of what is outside of the parenthesis to figure out the answer. Since it is ln 2 make that 1/x and plug in 2 therefore giving you the limit at ½.

The average rate of chage of function f on [1, 4] is..
You are given a table of the values
For this problem you use f(b) – f(a)/b – a
Therefore f(4) – f(1)/3 equals 6-2/3 which equals 4/3