Alright, so this week started off okay...
We took the first test on the slope field on Monday and it was only out of six points [i think] and we got the corrections to that on Thursday!
Then Tuesday we took the non-calculator portion of the AP exam.
QUESTIONS ON THIS PACKET:
number 9: I dont even know where to being. please explain!
number 15: How is x=2 a local minimum?
number 24: I tried it, but I get lost in my work!...help!
number 25: I don't know why I can't do this one, but every time I do it I don't get any of the possible answers.
number 27: same as 25
number 28: I still don't understand, or grasp, how to take the derivitive or integral of LN
WHAT I CAN POSSIBLY HELP WITH:
number 3: super easy, just careless mistakes...factor out an X and then use the quotient rule.
number 4: same thing, factor and then cancel out the (x-4)'s, so you're left with x-3 so plug in 4 leaving you with 1 for your answer!
Wednesday we took the calculator portion of the AP exam.
QUESTIONS ON THIS PACKET:
number 35: HELP..that's all I can say!
the rest, I'm going to try to work on!
WHAT I CAN POSSIBLY HELP WITH:
number 31: you're finding the limit as x is approaching zero to tan pi over six plus h minus tan pie over six, all over h. H H H H H H H H H H H when you see H in a problem it's the definition of a deriviative, so you just take the part that has H plus something, in this case H plus (pie over six) and take the derivative of it giving you sec^2(x) plug in (pie over six) for x giving you 4/3!!
number 32: if you're given 30-100 for A and 50-100 for B, and asked to find what 30-50 is then you can just see what's the difference of both. for instance, 100-30=70 and 100-50=50..take the two things you just found and subtract them because that's what the problem does so it's 70-50=20 which gives you the same answer as 50-30=20! Therefore, A-B is your answer!
THANKS JOHN for helping me with all of the other problems!!!
Thursday, Mrs. Robinson had a scare when she was having too much pain, so we went in A3. Some of us worked on corrections. Thank God I had some help!
Friday, Mrs. Robinson is not there and some of us worked on corrections again.
SOOO...MONDAY NIGHT...THAT CORRECTIONS PARTY AT RICKY'S .. SOMEONE SHOULD CALL ME! =)
~ElliE~
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If someone can post the questions I can help.... Didn't get to grab my packet with all the crazy.
ReplyDelete15. x=2 is not a local minimum because there is no change in the graph.
ReplyDelete24. You first have to get y's and x's on the same side so
cross multiply and you should get dy y = 3x^2 +2 dx
Next step is to integrate both sides remember + c goes to the right side.
1/2 y^2 = x^3 + 2x + c
Then plug in the x and y given to you and solve for c.
1/2 (4)^2 = (2)^3 + 2(2) + c
8= 8 + 4 + c
8 = 12 +c
c = -4
Once you found c, plug c and the x given into your integrated formula and solve for y.
1/2 y^2 = (3)^3 + 2(3) + -4
1/2 y^2 = 27 + 6 - 4
1/2 y^2 = 29
y^2 = 29 / 1/2
y^2 = 58
y = plus or minus the square root of 58
Hope you can follow that =)