Sunday, January 31, 2010

Post #24

hello, good afternoon, and welcome. Everyone seems like they are having trouble with ln integration and e integration..so i'm here to help with what i possibly can.

First things first, ln integration is the opposite of a derivative..so a derivative of ln x would be 1/x. Now, think backwards, the integral of ln x would be 2lnx, or ln x^2, in simplest terms.

e Integration is something i can attempt to help someone with..but i'm not quite sure i do it the right way.

So, here it goes i think you substitute the exponent for u and then du is the derivative of the exponent. Then, you plug in and solve the integral as it comes.

S e^2x would be
d= 2x
du = 2

1/2 S e^u du
..then i get confused.
whatever, i can't explain this.

So, things i don't understand are really small things while i'm solving..so i'm not sure anyone can help me in advance.

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