Saturday, February 6, 2010

25th post

This week in calculus we took some more AP exams. I did pretty well on the non-calculator portion but the calculator portion was a different story.

Things i know:

1. Limit rules:
if the degree on the top is bigger than the degree on the bottom, the limit is infinity
if the degree on the top is smaller than the degree on the botton, then limit is zero.
if the degree on the top is the same as the degree on the bottom, you divide the coefficients to get the limit.

2. First and Second derivative test:
Whenever a question is asking for relative max or min or whether the function is increasing or decreasing, you use the first derivative test. You take the derivative of the function, set the derivative equal to zero and solve for the x values (critical points). Then you set the critical points into intervals between negative infinity and infinity. Then you plug a number between those intervals to see whether the function is increasing or decreasing or if they are max or mins.

For absolute max or mins, you do the same steps, but if they give you a point, you have to plug those in as well. For absolute max and mins, you plug your values into the original function to find a y value. The point with the highest y values is an absolute max and the lowest y values is an absolute min.

For the second derivative test, you will find change in concavity and points of inflection. You take the derivative of the function twice and solve for critical values and set them up into intervals and plug in numbers between the intervals into the second derivative. This will tell you where there are changes in concavity and points of inflection.

Things i do not know:
1. Number 27 and 28 on the non-calculator portion
2.Number 35 on the calculator portion.
3. Number 39 and 40 on the calculator portion
4. Number 42 and 43 on the calculator portion
5.Number 44 and 45 on the calculator portion.

Have a great extended weekend and GO SAINTS :)

1 comment:

  1. for number 35 it's just taking the volume
    so you know that it's the integral of the top squared over the integral of the bottom squared; however, even though it gives you 0 and 2 it will actually be 0 and 9
    so it's pi times the integral from 0 to 9 of (9-x^2)^2 minus (9-3x)^2
    DO IT IN YOUR CALCULATORR
    you should get 48 pi
    [i think]

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