I know it's late, but oh well.
This week after stressing for the exam, we learned something new that I actually got!!! Implicit Derivatives.
So you know it is an implicit derivative if it deals with both x's and y's. You also have to remember that when taking the derivative of a y term, you must either put a y' after or dy/dx. So example problems! Yay!
x^3 - 3x^2 + 2xy^2 = 12
After doing product rules and simplifying, you get:
3x^2 - (3x^2 y' + 6xy) + 4xyy' + 2y^2 = 0
solving for y' you get (-3x^2 + 6xy - 2y^2)/(-3x^2 + 4xy).
A listof things to remember:
1. y derivative dx/dy or y'
2. productrules
3. derivative of constant is 0
4. When possible factor out dx/dy or y'
Could someonehlep me on the t problems like the ones inthe mulitple choice practice.
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