Post #10

OHHH MMMYYYYYY....i don't know what to say about this week in calculus. At the beginning things were looking up! We learned about Implicit Derivatives, that's something i know how to do sooo...

steps to IMPLICIT DERIVATIVES:
1. Take the derivative like normal.
2. For each y-term, you put y' or dy/dx behind it.
3. Solve for dy/dy or y'.

36x^2 + 2y = 9
36x + 2(dy/dx) = 0
2(dy/dx) = -36x
-36x/2
dy/dx = -18x

We then learned how to take the Second Implicit Derivative...

steps to SECOND IMPLICIT DERIVATIVES
1. Take the derivative of the first derivative
2. Put d^2y/dx^2 for dy/dx
3. Simplify
4. Plug in values

so an example using the same equation is:
we take the first implicit derivative FIRST...[durr]
36x^2 + 2y = 9
36x + 2(dy/dx) = 0
2(dy/dx) = -36x
-36x/2
dy/dx = -18x <-- that's our first implicit derivative

now in order to take the second implicit derivative we just take the second derivative of dy/dx = -18x..

dy/dx = -18x
dy/dx = -18
so since we know that dy/dx is -18x we can plug that in
-18x = -18
when solving for x we get 1!

those, i understand...now for what i really do have trouble with is ALL of the word problems and the Angles!
If someone would take the time and go step by step and tell me how you know what's what it would be GREATLY appreciated!
once again, THANKS for the help!