Saturday, October 24, 2009

Post #10

This week in calculus we learned related rates and angle of elevation.

The steps for related rates are:

1. Identify all your variables and equations. Some may be given, but some you may have to find.

2. Identify what you need to solve for.

3. Make a sketch or draw a picture of what you are given.

4. Take the derivative of the equations with respect to time.

5. Plug in given numbers to the derivative and solve.

EXAMPLE 1: The problem can be given as just and equation with given information such as :

x^2+y^2=25 dy/dt when x=3, y=4 dx/dt= 8

Derivative: 2x dx/dt + 2y dy/dt= 0

When you plug in you get: 2(3)(8) + 2(4) (dy/dt) = 0

48+ 8 dy/dt=0

dy/dt= -6


EXAMPLE 2: You may have to find the equation yourself:

The radius r of a circle is increasing at a rate of 3 centimeters per minute. Find the rates of change of the area when r=6 centimeters and when r=24 centimeters.

The area of a circle is A=pir^2

You are given dr/dt=3

Take the derivative of the equation: dA/dt=2pir (dr/dt)

Now plug into your derivative: dA/dt= 2pi(6)(3)

dA/dt= 36pi cm^2/min.
Using the same derivative, you plug in 24 into the equation instead of 6

dA/dt= 2 pi (24)(3)

dA/dt= 144 pi cm^2/min.

I understand the simple related rates problems such as these two; however, I don't understand how to work them when they get harder and give real life situations. The same thing applies for angle of elevation. I let the words get in the way and cannot find what they are asking for or what is given.

Help would be appreciated =)



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