Normal lines have the same steps and tangent lines but when you find the slope you have to take the reciprocal.
Example:
An equation of the line normal to the graph of y = (3x^2 +2x)^1/2 at (2,4) is
1. Since you already have a point, you do not need to plug in the x to find the y.
2. Derivative: 1/2 (3x^2 + 2x) ^ -1/2 (6x +2)
Plug in x to find slope: 6(2) +2 / 2 (3(2)^2 + 2(2)) ^1/2
14/8 = 7/4
Since this is normal, we need the negative reciprocal of the slope, which is -4/7
Plug in x to find slope: 6(2) +2 / 2 (3(2)^2 + 2(2)) ^1/2
14/8 = 7/4
Since this is normal, we need the negative reciprocal of the slope, which is -4/7
3. Now we can plug in: y-4 = -4/7 (x-2)
Than change what you got and find your awnser choice
Than change what you got and find your awnser choice
7y - 28 = -4 (x-2)
7y - 28 = -4x + 8
7y = -4x + 36
4x + 7y = 36
What i'm having trouble with is:
Someone help me find AREA,
and... Trapazoidal
To find area, you can use any of the reimann sums, and to find area on a graph, you find the area of all the shapes and add them together
ReplyDeletehere ya goooo.....
ReplyDeleteTrapezoidal- x/2[f(a)+2f(a+x)+2f(a+2x)+...f(b)]
Trapezoidal is the easiest formula to remember once you've got it down because none of the others are like it and it's just plugging in after you've got it
ReplyDeletedelta(x)=b-a/n
TRAM: delta(x)/2[f(a)}2f(a+delta(x))+2f(a+2delta(x))+2f(a+3delta(x))....+f(b)]