Sunday, March 7, 2010

Ash's 29th Post

So, I just want to say one thing before I start:
This last AP test seemed lake the HARDEST out of all of them so far.
That is all.

Also, this is going to be more of a clarification blog than an explaining blog..


On the non-calculator portion, I can get so far on some...and then just lose it, then on others I'm sooo lost

1. xSpi/4 cos(2t)dt
Step 1: Look at your answer choices
Well, A) and C) are out of the picture because, obviously, the integral of cos isn't cos...D) can also be taken out because the pi/4 wold not just disappear..
Step 2: Integrate
-sin(2pi/4)
-sin(2x)
Step 3: Solve
I have no idea how I did this (TRIG CHART), but the answer is sin(2x)-1/2
Can anyone explain how I got to the last part? Trig always scares me...

5. It's a graph with "the graph of the piecewise linear function, for 0 less than or equal to (LTET) x LTET 8 is shown above. what is the value of 8S0 f(x)dx" Can anyone explain it to me how to approach this and do it?

6. If f is continuous for a *LTET* x *LTET* b then at any point x=c, a LTET c LTET b, which of the following is true?
The answer is lim x->c f(x)=f(c)
Why? How can you figure that out?

7. if f(x) = x^2 sqrt(3x+1), then f'(x)=?
I can get this far, but get completely stuck in everything =/
1. x^2(3x+1)^1/2
2. 2x(3x+1)^1/2 + 1/2(3x+1)(3)(x^2)
ahh...can someone tell me what to do next? =/

10. This is another graph, but with velocity and distance. Can anyone explain it to me? I've never gotten graphs and I don't expect to...maybe there's a trick?


Thanks guys :)
Hope everyone had a good weekend!

7 comments:

  1. You did 7 right you just forgot to subtract from the exponent it should be

    2x(3x+1)^1/2 + 1/2(3x+1)^(-1/2)(3)(x^2)

    From there it is algebra simplification, The negative exponent makes it go to the bottom so you will get a fraction with sqrt(3x+1) in the denom. I don't have the answer choices on me but I am assuming you have to combine the fractions for the choices.

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  2. For number 5, all you have to do is divide the graph into shapes you know how to take the area of so triangles and rectangles. Once the graph is divided, find the area of each and add the areas. Because part of the graph is below the axis, you subtract the part above from the part below.

    The first shape is a triangle: (1/2)(2)(2) = 2
    Rectangle: (2)(2) = 4
    Triangle: (1/2)(1)(2) = 1
    Bottom of the graph is two triangles
    (1/2)(1)(2) = 1
    (1/2)(2)(2) = 2
    2+4+1 = 7
    1+2= 3
    7-3 = 4, so the answer is B.

    10 is worked the same way. Divide into shapes, find area of each shape, and add.
    Triangle: (1/2)(4)(60)=120
    Rectangle: (4)(30) = 120
    Rectangle: (4)(90)= 360
    Triangle: (1/2)(4)(90) = 180
    120+120+360+180= 780
    The answer is C.

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  3. You seperate the graph into individual triangles and rectangles.. you have to find the area of each individual rectangle or triangle and to find the area of the whole thing you have to add all the areas together. Do not forget, the area of a triangle is 1/2(base)(height) and the area of a rectangle is (base) (height).. hope this helps girl!

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  4. Ok, if you're looking at a graph that is asking to go from velocity to distance, you need to integrate it. To integrate a graph, you need to break it up into rectangles and triangles, find the area of each of them, and add them together to get your answer.

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  5. You need to seperate the graphs into triangles and rectangles and find the area of each. then u find the area of the entire thing and add all areas together.

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  6. you have to seperate the graph into basic triangles and rectangles and find the area of each one, then you add the areas together to get the area of the whole thing

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  7. We went over these in class I thought, but it's really easy. Break the graph up like eeryone else said but don't put shapes inside of shapes or anything crazy like that.. Break them up rationally into squares rectangles and triangles ( you have to know the area formula for these shapes). Once determining the area of each, add them all together to reach your answer.

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