This week was a lot of learning. We reviewed and took a quiz on limits and learned about Integration. I am having trouble with this stuff; I guess it just hasn't clicked yet.
We learned how to find the area under a curve and how to approximate this by using LRAM, RRAM, MRAM, or Trapezoidal. The two I'm most comfortable with is LRAM and RRAM.
Lets start with LRAM first:
f(x)=x^2-3 [1,4] n=3
First find your delta x:
(4-1)/3= 3/3= 1
Plug into formula next:
delta x=[f(a)+f(a+delta x)+...f(b+delta x)]
1[f(1)+f(2)+f(3)]
Use original equation to figure out f(1)..f(3):
1^2-3=3 2^2-3=1 3^2-3=6
1[-2+1+6]= 1[5]= 5
Next is RRAM:
f(x)=x^2-3 [1,4] n=3
Use the same steps, except the formula is delta x=[f(a+delta x)+...+f(b)]
delta x=1
1[f(2)+f(3)+f(4)]
1[1+6+13]= 1[20]= 20
I don't understand how to do MRAM. So, can someone explain that to me please?
Next we have this weird looking S, which means the opposite of a derivative. There are two types: indefinite and definite. Indefinites answer will be an EQUATION and a definites answer will be a NUMBER. It seems like a simple concept, but for some reason I confuse myself. One thing I do know is to ALWAYS put +C behind the equation for indefinite. I really need some extra practice with these kinds of problems.
Subscribe to:
Post Comments (Atom)
formula for MRAM is x[f(mid)+ f(mid)+..]
ReplyDeleteokay so say that they give you the points 1 2 3 and 4.
find the midpoint between each point..
so the midpoint of 1 and 2 is 1/2..and so on.
after you find the midpoint, plug in to the function. so if f(x)=2x plug in f(1/2)=2(1/2).
after you do that for each midpoin add them togetherrr! simple simple