After another week in calculus we have learned about linearization, but we also spent some time reviewing for a test on everthing we have learned up to this point. The reason why we are doing this is because we are now done completely with derivatives. But the way to pick out these problems is when it asks you to approximate. Also you use differentials to approximate the linearization. Differential is something that has been solved for dy or dx.
The steps for solving linearization problems are:
1. Pick out the equation
2. f(x)+f`(x)dx
3. Figure out your dx
4. Figure out your x
5. Plug in everything you get
Also I am very comfortable with tangent lines. All you do is:
1. Take the derivative of the equation
2. Plug in the x value which gives you your slope
3. Use the slope you get and the point given and plug into slope intercept form (y-y1)=slope(x-x1)
*If a point is not given and only an x value is given plug the x value into the original which will give you a y value creating a point.
I did also learn a trick that helped me some with optimization. I learned that if you are looking for the optimization of a rectangle the answer will turn out to be a square.
I am not comfortable with problems like number 2 on the packet she gave us. It has to do with velocity. Also if someone could refresh my memory on instantaneous speed steps it would be appreciated because I can not seem to be able to find my notes on this.
Subscribe to:
Post Comments (Atom)
Instantaneous speed is simple.
ReplyDeleteYou take the derivative of the position function and then plug in. Instantaneous speed is basically the slope at a particular point in time of a position function.
So take derivative, plug in for t.