The second week of calculus is over!  Although I think Calculus is still one of my hardest classes, it's getting better.  I am understanding everything a lot better, and I've learned that it's good to ask questions. 
Something I understoood this week was the natural log properties.  You simply plug everthing into the formula and simplify.  Let's say we have ln(x^2).  You plug into the ln formula, 1/u * u', and you get 1/x^2 * 2x.  When you multiply you get 2x/x^2 which simplifies to 2/x (you cancel the x's).  I also understand that you may have to deal with multiple formulas in one problem.  An example would be ln(x/(x^2 + 1)).  In this problem you can see that you have to deal with natural log and quotient rule.  You would plug it into 1/u * u' first and then into the u prime you would do the quotient rule, (vu' - uv') / v^2.  
I also still get everything from last year with just normal logs.  Take log 1000 = x.  You would take away the log and swap 1000 and x.  You then have 10^x = 1000.  So from algebra you would know that 10^3 = 1000.  So x = 3 would be your answer.
Something I don't understand is the difference from u^n and a^u.  Take the example (ln x)^4.  Would you plug it into u^n = nu^(n-1) or a^u = a^ulna * u'?  I am still unsure about the whole concept. 
Hope this helped somebody.
Ryan.
Sunday, August 30, 2009
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a^u is only used when a is a number.
ReplyDeleteu^n is what you would use for (lnx)^4 because that is NOT a number.