ok that's what i've been doing, but i'm not sure if it's right...for this one, would it be: 5(-csc^2(x))+cot(x)(5) which would take out the stuff from the plus on cause 5 is zero? oh and then you have 2tan(x) so that would be: 2(sec^2(x))+ tan(x) (2) and the two is zeor? so total it would be: 5(-csc^2(x))+ 2(sec^2(x)) would that be the answer??
THe answer would be 5csc^2(x) + 5sec^2(x) you don't do a product rule. We went over that today in class. If there is a number in front you just ignore it. You don't need to keep taking derivatives you had it in the first line.
If you look in your notes the prime tells you to take a derivative.
ReplyDeleteok that's what i've been doing, but i'm not sure if it's right...for this one, would it be:
ReplyDelete5(-csc^2(x))+cot(x)(5) which would take out the stuff from the plus on cause 5 is zero?
oh and then you have 2tan(x) so that would be:
2(sec^2(x))+ tan(x) (2) and the two is zeor?
so total it would be:
5(-csc^2(x))+ 2(sec^2(x))
would that be the answer??
THe answer would be 5csc^2(x) + 5sec^2(x) you don't do a product rule. We went over that today in class. If there is a number in front you just ignore it. You don't need to keep taking derivatives you had it in the first line.
ReplyDeleteso what happened to the negatives was the derivatives??
ReplyDeleteoh and what about after the + sign... shouldn't it be 2 sec^2(x) instead of the 5
ReplyDeleteyea csc should be -ve and it should be a 2. For some reason I could swear I read two fives.
ReplyDeletelol..ok so just the csc is neg...
ReplyDeletei thought it would be a neg. sec too...right?
oh no nvm..i looked at the wrong thing too..sorry
ReplyDeleteTHANKSSS...
ReplyDeleteNo problem
ReplyDelete